Check given number is armstrong number

Armstrong number is a number in which sum of the cubes of all digits equals the number.

371 = 3^3 + 7^3 + 1^3

Code

#include<stdio.h>

int main()
{

    int sum=0,rem,no,n;

    printf("Enter a number ");
    scanf("%d",&no);

    n = no;

    while(n != 0)
    {
        rem = n % 10;
        sum = sum + rem * rem * rem;
        n = n/10;
    }

    if(no == sum)
        printf("\nArmstrong number");
    else
        printf("\nNot a armstrong number");

        return 0;
}

O/P

Code Tracing

Let no = 371

rem = 371 % 10 = 1
sum = 0 + 1 * 1 * 1 = 1
n = 371/10 = 37

rem = 37 % 10 = 7
sum = 1 + 7 * 7 * 7 = 344
n = 37/10 = 3

rem = 3 % 10 = 3
sum = 344 + 3 * 3 * 3 = 371
n = 3/10 = 0    STOP